Answer:
108, 110, 112
Explanation:
You want three consecutive even integers whose sum is 330.
Expression
Let x represent the middle integer. Then the other two are (x-2) and (x+2). The expression for their sum is ...
(x -2) +x +(x +2) = 330 . . . . . an algebraic expression
3x = 330
x = 110
x -2 = 108
x +2 = 112
The three integers are 108, 110, 112.
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Additional comment
"Consecutive integer" problems are often worked easily by considering the average value of the integers. For three consecutive integers, their average is the middle one.
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