What is an equation of the line that passes through the point (5,-5)(5,−5) and is parallel to the line x+5y=20?

Question

asked Mar 11, 2024 215k views

1 Answer

Jeshua Lacock · Answer 1 · 2024-03-15T11:54:20+0000

Answer:

y = -x/5 -4.

Explanation:

To simplify the line x + 5y = 20 into y = mx + b form:

x + 5y = 20.

5y = -x + 20.

y = -x/5 + 4.

The line parallel to the line y = -x/5 + 4 will have the same slope of -1/5.

We get the equation:

y = -x/5 + b.

To find b, we plug in the point (5, -5).

-5 = -5/5 + b.

-5 = -1 + b.

b = -4.

y = -x/5 -4.