Answer:Therefore, the cost of a utility pole with a diameter of 42 cm and a height of 740 cm is approximately $1957.43.
Step-by-step explanation:First, we need to calculate the volume of the cylinder-shaped utility pole:
The radius of the pole is half the diameter, so it's 42 cm / 2 = 21 cm.
The height of the pole is 740 cm.
The volume of a cylinder is given by the formula V = πr²h, where π is approximately 3.14, r is the radius, and h is the height.
Substituting the values we have, we get V = 3.14 x 21² x 740 = 1,034,462.4 cm³.
Now we can calculate the mass of the pole:
The density of the metal is 6.3 g/cm³, which means that 1 cm³ of the metal has a mass of 6.3 g.
The volume of the pole is 1,034,462.4 cm³, so its mass is 6.3 x 1,034,462.4 = 6,524,772.72 g.
Next, we convert the mass to kilograms and calculate the cost:
1 kg is equal to 1000 g, so the mass of the pole in kilograms is 6,524,772.72 g / 1000 = 6524.77 kg.
The cost of the metal is $0.30 per kilogram, so the cost of the pole is 6524.77 kg x $0.30/kg = $1957.43.