Answer:
y = -x^2-2x-2
Explanation:
vertex form = y=a(x-h)^2+k
standard form = y=ax^2+bx+c
the most straightforward way to solve it is to expand the vertex form
we get :
-(x+1)(x+1)-1
= -(x^2+x+x+1) - 1
note: remember to leave the negative sign out of the parentheses and distribute it after - otherwise you may mix up signs
= (-x^2-x-x-1) - 1
= -x^2-2x-1-1
= -x^2 - 2x - 2
So, in standard form, it is y=-x^2-2x-2
Hope this helps!