Question

What is this from vertex to standard form ?

Answer 1

y = -x^2-2x-2

Explanation:

vertex form = y=a(x-h)^2+k

standard form = y=ax^2+bx+c

the most straightforward way to solve it is to expand the vertex form

we get :

-(x+1)(x+1)-1

= -(x^2+x+x+1) - 1

note: remember to leave the negative sign out of the parentheses and distribute it after - otherwise you may mix up signs

= (-x^2-x-x-1) - 1

= -x^2-2x-1-1

= -x^2 - 2x - 2

So, in standard form, it is y=-x^2-2x-2

Hope this helps!