Answer:
b. g(t) = 1.5 sin (π t) +3.5
Explanation:
You want to choose the function that has the given graph.
Test points
At t = 0, the graph shows a value of 3.5. The sine of 0 is 0, so this eliminates choice A.
At t = 1/2, the graph shows a value of 5. The values given by the different formulas are ...
b. g(1/2) = 1.5·sin(π/2) +3.5 = 5 . . . . . matches the graph
c. h(1/2) = 1.5·sin(π) + 3.5 = 3.5 . . . . no match
d. h(1/2) = 1.5·sin(π/4) +3.5 = 0.75√2 +3.5 . . . . no match
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Additional comment
The horizontal distance for one period of the graph (from peak to peak, for example) is T = 2 seconds. If the sine function is sin(ωt), then the value of ω is ...
ω = 2π/T = 2π/2 = π
This tells you the function g(t) = 1.5·sin(πt)+3.5 is the correct choice.