Question

As clothing tumble in a dryer, they can become charged. If a small piece of lint with a charge of +1.62 E−19 C is attracted to the clothing by a force of 2.0 E−9 N, what is the magnitude of the electric field at this location?

0.38 E10 N/C
1.2 E10 N/C
3.2 E10 N/C
3.6 E10 N/C

Answer 1

Answer:

option (b) 1.2E10 N/C.

Step-by-step explanation:

The electric field (E) can be calculated using the formula:

E = F/q

where F is the force on the lint, and q is the charge on the lint.

Substituting the given values, we get:

E = (2.0E-9 N) / (1.62E-19 C)

E ≈ 1.23E10 N/C

Therefore, the magnitude of the electric field at the location is approximately 1.23 x 10^10 N/C, which is closest to option (b) 1.2E10 N/C.