Question

What quantity of heat (in J) would be required to convert 0.27 mol of a pure substance from a liquid at 50 °C to a gas at 113.0 °C?.

Cliquid = 1.45 J/mol C
Cgas = 0.65 J/mol *C
Tboiling = 88.5 °C
AHvaporization = 1.23 kJ/mol
Give your answer in Joules

Answer 1

Step-by-step explanation:

First you have to heat the liquid from 50 to 88.5 C to get it boiling...

then you need to boil it all to a gas....the you have to heat it to 113 C

.27 mole *

( (88.5 -50 C)*1.45 J / (mole-C) <====heating the liquid

+ 1230 J / mole <====boiling to a gas

+ (113 - 88.5 C) * .65 J/(mole C) <=====heating the gas

= 351 .5 J <=====result