Question

Find, from first principle the deriva- tive of 1/(x²+1)
​

Answer 1

Explanation:

`\frac{1}{( {x}^(2) + 1) } = (u)/(v)`

u = 1

u' = 0

v = x² + 1

v' = 2x

`\frac{1}{ ({x}^(2) + 1)} \\ = \frac{u'v - v'u}{ {v}^(2) } \\ = \frac{0 - (2x * 1)}{ {( {x}^(2) + 1)}^(2) } \\ = - \frac{2x}{ { ({x}^(2) + 1) }^(2) }`

#CMIIW