Question

Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. Find the Position of centre of mass of the system from the corner A.

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Answer 1

The center of mass of the system can be found by taking the weighted average of the positions of the individual masses.

Let's call the mass at point A M1, the mass at point B M2, the mass at point C M3, and the mass at point D M4.

The x-coordinate of the center of mass is given by:
x_cm = (M1*x1 + M2*x2 + M3*x3 + M4*x4) / (M1 + M2 + M3 + M4)

The y-coordinate of the center of mass is given by:
y_cm = (M1*y1 + M2*y2 + M3*y3 + M4*y4) / (M1 + M2 + M3 + M4)

We know that the distance between any two adjacent corners of the square is 2cm. Therefore, we can say that the coordinates of the four masses are:
M1 = 2kg at (0,0)
M2 = 4kg at (2,0)
M3 = 6kg at (2,2)
M4 = 8kg at (0,2)

Substituting these values into the equations above, we get:
x_cm = (2*0 + 4*2 + 6*2 + 8*0) / (2 + 4 + 6 + 8) = 2
y_cm = (2*0 + 4*0 + 6*2 + 8*2) / (2 + 4 + 6 + 8) = 2

Therefore, the center of mass of the system is located at a distance of 2cm from corner A along the x-axis and 2cm from corner A along the y-axis.