Question

A 12 V battery is connected across two parallel metal plates separated by 0.59 cm. Find the magnitude of the electric field.

Answer 1

The magnitude of the electric field between two parallel plates is given by:

E = V/d

where V is the potential difference between the plates and d is the distance between them.

In this case, V = 12 V and d = 0.59 cm = 0.0059 m. Substituting these values, we get:

E = 12 V / 0.0059 m

E = 2033.9 V/m

Therefore, the magnitude of the electric field is 2033.9 V/m.