Question

1 Consider a ring, sphere and Solidey clinder all with the same mass. They are all held at the top of the inclined Plane which is at 20° to the horizontal. the top of the inclined Plane is 1m high. The shapes are released simultaneously and allowed to roll down the inclined plane. Assume the abjects roll with out slipping and that they are all made from the same material. Assume the coefficient of static friction bin the objects and the plane is 0.3.

A) which shapes have the greater moment of inertia ?
B) workout what order they would get to the bottom of the Slope!
C ) determine the linear acceleration(a)
D) calculate the tangential (linear) Veloci ty of each shapes
E) How long will it take each shape to reach the bottom of the Slope ?
I give you 100 coin please help me


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Answer 1

A) The solid cylinder has the greatest moment of inertia, followed by the ring, and then the sphere.

B) The solid cylinder will reach the bottom of the slope first, followed by the sphere, and then the ring.

C) The linear acceleration of the objects can be calculated using the following formula:

a = g * sin(θ) / (1 + I / mr^2)

where g is the acceleration due to gravity, θ is the angle of the incline, I is the moment of inertia, m is the mass, and r is the radius of the object.

Plugging in the numbers, we get:

a_ring = 9.8 m/s^2 * sin(20°) / (1 + 0.5 / 1^2) = 1.09 m/s^2
a_sphere = 9.8 m/s^2 * sin(20°) / (1 + 2 / 1^2) = 0.84 m/s^2
a_cylinder = 9.8 m/s^2 * sin(20°) / (1 + 0.5 / 0.5^2) = 1.47 m/s^2

Therefore, the linear accelerations are a_ring = 1.09 m/s^2, a_sphere = 0.84 m/s^2, and a_cylinder = 1.47 m/s^2.

D) The tangential velocity of each object can be calculated using the following formula:

v = a * r

where a is the linear acceleration, and r is the radius of the object.

Plugging in the numbers, we get:

v_ring = 1.09 m/s^2 * 0.5 m = 0.55 m/s
v_sphere = 0.84 m/s^2 * 1 m = 0.84 m/s
v_cylinder = 1.47 m/s^2 * 0.5 m = 0.74 m/s

Therefore, the tangential velocities are v_ring = 0.55 m/s, v_sphere = 0.84 m/s, and v_cylinder = 0.74 m/s.

E) The time it takes for each object to reach the bottom of the slope can be calculated using the following formula:

t = sqrt(2 * d / a)

where d is the distance traveled, and a is the linear acceleration.

Plugging in the numbers


A) The solid cylinder has the greatest moment of inertia.
B) The order in which the objects would reach the bottom of the slope is: sphere, cylinder, and ring.
C) The linear acceleration of each object is the same and is equal to 0.98 m/s^2.
D) The tangential velocity of the sphere, cylinder, and ring are 2.78 m/s, 3.53 m/s, and 4.24 m/s, respectively.
E) The time it takes for each object to reach the bottom of the slope can be calculated using the following formula:

time = square root(2h / g)

where h is the height of the slope (1m) and g is the acceleration due to gravity (9.8 m/s^2).

Plugging in the numbers, we get:

time for sphere = 0.45 s
time for cylinder = 0.51 s
time for ring = 0.57 s

Therefore, the sphere would reach the bottom first, followed by the cylinder, and then the ring.