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29, 58,116, Find the 7th term.

1 Answer

9 votes

9514 1404 393

Answer:

1856

Explanation:

The numbers given do not have a common difference, but they do have a common ratio:

58/29 = 116/58 = 2

The general term of a geometric sequence with first term a1 and common ratio r is ...

an = a1×r^(n-1)

For this sequence, a1=29 and r=2, so the general term is ...

an = 29×2^(n-1)

Then the 7th term is ...

a7 = 29×2^(7-1) = 29×64 = 1856

The 7th term is 1856.

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If you prefer, you can double each term until you have 7 of them.

29, 58, 116, 232, 464, 928, 1856, ...

User Viraj Tank
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