135k views
5 votes
Zinc reacts with HCl to produce hydrogen gas, H2, and ZnCl2.

Zn(s) + 2 HCl(aq) --> H2(g) + ZnCl2(aq)

How many liters of a 1.50 M HCl solution completely react with 5.32 g of zinc?

1 Answer

3 votes

Answer:

0.108L HCl

Step-by-step explanation:

5.32 g zinc * 1 mol zinc/65.38g zinc * 2 mol HCl/1 mol zinc * L HCl/1.5 mol HCl = 0.108L HCl

User ITisha
by
8.5k points