Question

The vertices of AABC are A (-3, -6), B (-3,5), and C (5,5).
What is the area of AABC?

Answer 1

• 44 units²

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AB is vertical with same x-coordinates, and BC is horizontal with same y-coordinates.

Hence this is a right triangle.

Its area is:

• A = 1/2 × AB × BC
• A = 1/2(5 - (-6))(5 - (-3)) = 1/2(11)(8) = 44 units²