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How do you calculate the concentration of obtained solution with 2 solutions having the same concentration but different volume?

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50.0cm³ of 0.0250 mol/dm³ nitric acid was mixed with 40.0 cm³ of 0.0250 mol dm/³ sulfuric acid. ​

User Srigar
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1 Answer

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To calculate the concentration of the resulting solution, we need to use the principle of conservation of moles. This principle states that the number of moles of a chemical species is conserved when it is mixed with another chemical species. We can use the following formula to calculate the concentration of the resulting solution:

C1V1 + C2V2 = C3V3

where C1 and V1 are the concentration and volume of the first solution, C2 and V2 are the concentration and volume of the second solution, and C3 and V3 are the concentration and volume of the resulting solution.

In this case, we have:

C1 = 0.0250 mol/dm³ (nitric acid)
V1 = 50.0 cm³ (nitric acid)
C2 = 0.0250 mol/dm³ (sulfuric acid)
V2 = 40.0 cm³ (sulfuric acid)

We want to find C3, the concentration of the resulting solution. We can rearrange the formula to solve for C3:

C3 = (C1V1 + C2V2) / V3

where V3 is the total volume of the resulting solution, which is the sum of the volumes of the two solutions:

V3 = V1 + V2 = 50.0 cm³ + 40.0 cm³ = 90.0 cm³

Substituting the values, we get:

C3 = (0.0250 mol/dm³ x 50.0 cm³ + 0.0250 mol/dm³ x 40.0 cm³) / 90.0 cm³

C3 = 0.0250 mol/dm³

Therefore, the concentration of the resulting solution is 0.0250 mol/dm³, which is the same as the concentration of the two original solutions.
User Daniel Magliola
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