Question

A flashlight bulb is connected to a dry cell of voltage 5.25 V. It draws 15 mA (1,000 mA = 1 A). Its resistance is

2.5 E2 ohms
3.0 E2 ohms
3.5 E2 ohms
4.0 E2 ohms

Answer 1

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C) 3.5 Ω

Ohm's Law:

R = V / I × 10

= 5.25 ÷ 15mAh × 10

= 3.5 Ω

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