Since $\triangle KLM$ is a right triangle, we can use the Pythagorean Theorem to find the length of $KM$:
\[KM = \sqrt{KL^2 + LM^2} = \sqrt{8^2 + 6^2} = \sqrt{64+36} = \sqrt{100} = 10.\]
Now we can use the definition of sine:
\[\sin \angle M = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{LM}{KM} = \frac{6}{10} = \boxed{\textbf{(A)}\ \frac{10}{12}}.\]