Answer:
The correct answer is C.
The packet sequence number is stored in bits 1-4, which in this case is 10011100. This is equal to 23 in decimal.
The total number of packets in the message is stored in bits 5-8, which in this case is 01010110. This is equal to 22 in decimal.
Therefore, this is packet 23 out of 22 total packets in the message.
* * *
Here is a breakdown of the bits in the packet:
```
Bits | Description
------- | --------
1-4 | Packet sequence number
5-8 | Total number of packets in the message
9-16 | Sender ID
17-24 | Receiver ID
25-64 | Message data
`