8.7k views
0 votes
Calculate the value of Kp at 227 degrees Celsius for the equilibrium: 3 A(g) ⇌ B(g) + D(g Kc=5.15

User Dunxd
by
8.1k points

1 Answer

7 votes
To calculate the value of Kp, we need to use the relationship between Kp and Kc, which is:

Kp = Kc x (RT)^Δn

where R is the gas constant (0.082 L atm/mol K), T is the temperature in Kelvin, and Δn is the difference in the number of moles of gas on the product side and the reactant side (in this case, Δn = 2-3 = -1).

First, we need to convert the temperature from Celsius to Kelvin:

T = 227°C + 273.15 = 500.15 K

Next, we can plug in the values into the equation:

Kp = Kc x (RT)^Δn
Kp = 5.15 x (0.082 L atm/mol K x 500.15 K)^-1
Kp = 5.15 x (20.33 L/mol)^-1
Kp = 0.125 atm^-1

Therefore, the value of Kp at 227 degrees Celsius for the equilibrium 3A(g) ⇌ B(g) + D(g) with Kc=5.15 is 0.125 atm^-1.
User Voondo
by
7.8k points