Question

32 = 4(n – 5) and -s + 11 = 17 please solved Both of the following​

Answer 1

Explanation:

Let's solve your system by substitution.

32=4(n−5);−s+11=17

Rewrite equations:

32=4n−20;−s+11=17

Step: Solve 32=4n−20 for n:

32=4n−20

32+−4n=4n−20+−4n(Add -4n to both sides)

−4n+32=−20

−4n+32+−32=−20+−32(Add -32 to both sides)

−4n=−52

−4n/ −4 =/ −52/ −4

(Divide both sides by -4)

n=13

Step: Substitute 13 for n in −s+11=17:

−s+11=17

−s+11=17

−s+11+−11=17+−11(Add -11 to both sides)

−s=6

−s/ −1 = 6/ −1

(Divide both sides by -1)

s=−6

Answer:

n=13 and s=−6

Answer 2

n=13 s=-6

Explanation:

Hope this helps :)