Question

I need help with this real quick please

Answer 1

First, using the Pythagorean theorem, we get the hypotenuse = 12.

sin = opposite/hypotenuse =
`(6√(3) )/(12) = (√(3) )/(2)`

cos = adjacent/hypotenuse =
`(6)/(12) =(1)/(2)`

tan = opposite/adjacent =
`(6√(3) )/(6) = √(3)`

csc = hypotenuse/opposite =
`(12)/(6√(3) ) =(2)/(√(3) )`

sec = hypotenuse/adjacent =
`(12)/(6) =2`

cot = adjacent/opposite =
`(6)/(6√(3) ) = (1)/(√(3) )`