Answer:
- 5) 3003 ways;
- 6) 252 ways.
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5) Use the combination formula:
- C(n, r) = n! / (r!(n-r)!)
In this case, n = 15 (total students) and r = 5 (students in a group).
Substitute and calculate:
- C(15, 5) = 15! / (5!(15-5)!)
- C(15, 5) = 15! / (5!10!)
- C(15, 5) = 3003
The teacher can combine the students in 3003 ways for the first group.
6) After the first group of five is selected, there are 10 students remaining.
Again use the combination formula, with n = 10 and r = 5:
- C(10, 5) = 10! / (5!(10-5)!)
- C(10, 5) = 10! / (5!5!)
- C(10, 5) = 252
The teacher can combine the remaining students in 252 ways for the second group.