Question

Simplify

(2a² b c³) (-a² b⁵)

pls help asap!​

Answer 1

Answer: -2
`a^(4)`
`b^(6)`c³

Explanation:

Given:

(2a² b c³) (-a² b⁵)

Rules:

>Multiply numbers first

>If a number with an exponent is multiplied to another, you can combine if the bases are the same(lower number)

>If they have the same base, you can add the exponents

Solution:

(2a² b c³) (-a² b⁵) >multiply the - and 2

-2(a² b c³) (a² b⁵) > combine the a's by adding the expnents 2+2

-2
`a^(4)`( b c³) ( b⁵) > combine b, there is an invisible 1 by the first b 1+5

-2
`a^(4)`
`b^(6)`c³ >c stays as is because nothing to combine with

Answer 2

`-2a^(4)b^(6) c^(3)`

Explanation:

(2a² b c³) (-a² b⁵)

distribute amongst each other

-2a²bc³a²b⁵

rearrange

-2a²a²bb⁵c³

combine like terms

`-2a^(4)b^(6) c^(3)`

Hope this helps!