We are given the annual depreciation rate function $r=1-\sqrt[3]{\frac{S}{5000}}$, where $S$ is the current value of the technology. We want to find the value of $S$ after 3 years, when $r=0.15$.
First, we can solve the equation $r=1-\sqrt[3]{\frac{S}{5000}}$ for $S$, to get:
$\sqrt[3]{\frac{S}{5000}} = 1-r$
Cubing both sides, we get:
$\frac{S}{5000} = (1-r)^3$
Multiplying both sides by 5000, we get:
$S = 5000(1-r)^3$
Now, we can substitute $r=0.15$ into this equation, to get:
$S = 5000(1-0.15)^3$
Simplifying:
$S = 5000(0.85)^3$
$S = 5000(0.614125)$
$S = 3070.63$
Therefore, the value of the technology after 3 years is $S = \$3070.63$.