Question

You sold a total of 320 student and adult tickets for a total of $1200. Student

tickets cost $3 and adult tickets cost $8. How many adult tickets were sold?

Answer 1

Let's use algebra to solve the problem.

Let x be the number of student tickets sold, and y be the number of adult tickets sold.

We know that the total number of tickets sold is 320, so:

x + y = 320

We also know that the total revenue from ticket sales is $1200, so:

3x + 8y = 1200

Now we can solve for one of the variables. Let's solve for x:

x = 320 - y

Substitute this expression for x in the second equation:

3(320 - y) + 8y = 1200

960 - 3y + 8y = 1200

5y = 240

y = 48

Therefore, 48 adult tickets were sold. To find the number of student tickets sold, substitute y = 48 into the first equation:

x + 48 = 320

x = 272

Therefore, 272 student tickets were sold.

Answer 2

48 adult tickets were sold.

Explanation:

Let's use algebra to solve this problem:

Let's define:

• x: the number of student tickets sold
• y: the number of adult tickets sold

From the problem statement, we know:

• x + y = 320 (the total number of tickets sold is 320)
• 3x + 8y = 1200 (the total revenue from ticket sales is $1200)

We can use the first equation to solve for x in terms of y:

x = 320 - y

Substituting this expression for x into the second equation, we get:

3(320 - y) + 8y = 1200

Expanding the left side, we get:

960 - 3y + 8y = 1200

Simplifying, we get:

5y = 240

Solving for y, we get:

y = 48

Therefore, 48 adult tickets were sold.

Additional:

To find the number of student tickets sold, we can substitute y=48 into the first equation:

x + 48 = 320

x = 272

Therefore, 272 student tickets were sold.