Question

The density of water is 1.0g/cm3. How many kilograms of water does a submerged 120-cm3 block displace? Recall that 1.0 kg weighs 9.8 N on Earth. What is the buoyant force on the block?

Answer 1

• The mass of the liquid displaced is 0.12 kg

• The buoyant force on the block is 1.176 N.

Step-by-step explanation:

Given;

density of water, ρ = 1.0 g/cm³

volume of the submerged block, V = 120 cm³

Applying Archimedes principle;

The mass of the liquid displaced is calculated as;

m = ρV

m = 1.0 g/cm³ x 120 cm³

m = 120 g

m = 0.12 kg

The buoyant force on the block is calculated as;

F = mg

F = 0.12 x 9.8

F = 1.176 N

Therefore, the buoyant force on the block is 1.176 N.