Question

What is the equation of the line that is parallel to the linear graph of y=2x-1 and passes through the point (-1,1)?

Answer 1

Answer: C. y=2x+3

Explanation:

Given:

y=2x-1 and new line passes through (-1,1)

Rules:

>A line is parallel to another line if the slopes are the same.

>Also, y=mx+b m=slope b=y-intercept

Solution:

y=2x-1 In the line given equation slope m=2 so slope for the new line will be the same

m=2 (-1,1) =
`(x_(1) ,y_(1))` because you now have the slope and a point. Use point

slope form to write an equation

`y-y_(1) =m(x-x_(1) )`

y-1=2(x-(-1)) > simplify

y-1=2(x+1) > distribute

y-1=2x+2 > add 1 to both sides

y=2x+3

Answer 2

y=2x+3 or option C is the correct answer.