Question

A truck travels up a hill with a 7.20◦

incline.
The truck has a constant speed of 26.0 m/s.
What is the horizontal component of the
truck’s velocity?

Answer 1

The horizontal component of the truck's velocity is given by:

v_horizontal = v_total * cos(theta)

where v_total is the total velocity of the truck and theta is the angle of the incline.

In this case, the total velocity of the truck is given as 26.0 m/s, and the angle of the incline is 7.20 degrees. We need to convert the angle to radians before we can use it in the equation:

theta = 7.20 degrees * (pi/180 degrees) = 0.1257 radians

Now we can substitute the values into the equation and solve for the horizontal component of the velocity:

v_horizontal = 26.0 m/s * cos(0.1257 radians) = 25.8 m/s (rounded to one decimal place)

Therefore, the horizontal component of the truck's velocity is 25.8 m/s.

Answer 2

#8

Step-by-step explanation:

26 m/s * cos (7.20) = 25.9 m/s