Answer:
thus: x = 5, y = -3
Explanation:
Solve the following system:
{y + x = 2 | (equation 1)
-4 y + 3 x = 27 | (equation 2)
Swap equation 1 with equation 2:
{3 x - 4 y = 27 | (equation 1)
x + y = 2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x - 4 y = 27 | (equation 1)
0 x + (7 y)/3 = -7 | (equation 2)
Multiply equation 2 by 3/7:
{3 x - 4 y = 27 | (equation 1)
0 x + y = -3 | (equation 2)
Add 4 × (equation 2) to equation 1:
{3 x + 0 y = 15 | (equation 1)
0 x + y = -3 | (equation 2)
Divide equation 1 by 3:
{x + 0 y = 5 | (equation 1)
0 x + y = -3 | (equation 2)
Collect results:
Answer: {x = 5, y = -3