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A. start fraction 3 over 2 end fraction

B. 1
C. –1
D. –start fraction 3 over 2 end fraction

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A. start fraction 3 over 2 end fraction B. 1 C. –1 D. –start fraction 3 over 2 end-example-1
User Vinze
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1 Answer

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to get the slope of any straight line, we simply need two points off of it, let's use those two in the picture below


(\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{1}-\stackrel{y1}{5}}}{\underset{\textit{\large run}} {\underset{x_2}{2}-\underset{x_1}{(-2)}}} \implies \cfrac{-4}{2 +2} \implies \cfrac{ -4 }{ 4 } \implies - 1

A. start fraction 3 over 2 end fraction B. 1 C. –1 D. –start fraction 3 over 2 end-example-1
User Rahulg
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