Question

In circle L with m/KLM = 42° and KL = 13, find the area of sector KLM.

Round to the nearest hundredth.
K
M
L

Answer 1

`\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ \theta =42\\ r=13 \end{cases}\implies A=\cfrac{(42)\pi (13)^2}{360} \\\\\\ A=\cfrac{1183\pi }{60}\implies \implies A\approx 61.94`