92.3k views
5 votes
Please answer this question . when you solve it please explain how you got the answer . thank you.



Please answer this question . when you solve it please explain how you got the answer-example-1

1 Answer

5 votes

Answer:

210°

Explanation:

You want the angle in standard position to the point (-√3, -1).

Angle

The angle θ in standard position to a point (x, y) can be found from ...

tan(θ) = y/x

θ = arctan(y/x)

The arctangent function gives an angle between -90° and +90°, so will give the value of the reference angle in this case. To find the angle in quadrant III, we must add 180° to the reference angle.

θ = arctan(-1/-√3) + 180° = 210°

The angle shown is 210°.

__

Additional comment

If you draw a vertical line from the point to the x-axis, you have a right triangle with side lengths 1 and √3. You know from your memory of special right triangles that this is a 30°-60°-90° triangle, whose smallest angle is 30°. This is the reference angle, so the angle of interest is 180° +30° = 210°.

Please answer this question . when you solve it please explain how you got the answer-example-1
User NeedAnswers
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories