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A bale of hay in the shape of a rectangular prism has a length of 4 feet, a width of 2 feet, and a height of 2 feet. A cylindrical bale of hay has a diameter of 8 feet and a height of 6 feet. How many rectangular bales contain the same amount of hay as one cylindrical bale? Round your answer to the nearest tenth.

User Nam Nguyen
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I donno where on Eart do you find those questions from.lol.

Explanation:

The volume of the rectangular bale of hay can be calculated using the formula:

V = lwh

where l, w, and h are the length, width, and height of the bale, respectively.

Substituting the given values, we get:

V = (4)(2)(2) = 16 cubic feet

The volume of the cylindrical bale of hay can be calculated using the formula:

V = πr^2h

where r is the radius of the bale (half the diameter), and h is the height of the bale.

Substituting the given values, we get:

V = π(4)^2(6) = 301.59 cubic feet

To find out how many rectangular bales contain the same amount of hay as one cylindrical bale, we can divide the volume of the cylindrical bale by the volume of one rectangular bale:

301.59 cubic feet / 16 cubic feet ≈ 18.85

Therefore, approximately 18.85 rectangular bales are required to contain the same amount of hay as one cylindrical bale. Rounded to the nearest tenth, this is 18.9 rectangular bales.

User Corbie
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