Step-by-step explanation:
From the balanced chemical equation, we see that 4 moles of FeS2 react with 11 moles of O2 to form 2 moles of Fe2O3.
So, for every 4 moles of FeS2, we get 2 moles of Fe2O3.
To find the moles of Fe2O3 formed from 14.56 moles of FeS2, we can use a proportion:
4 moles FeS2 / 2 moles Fe2O3 = 14.56 moles FeS2 / x moles Fe2O3
Cross-multiplying, we get:
4 moles FeS2 * x moles Fe2O3 = 2 moles Fe2O3 * 14.56 moles FeS2
Simplifying, we get:
x moles Fe2O3 = (2 moles Fe2O3 * 14.56 moles FeS2) / 4 moles FeS2
x moles Fe2O3 = 7.28 moles Fe2O3
Therefore, 7.28 moles of Fe2O3 will be formed when 14.56 moles of FeS2 reacts.