Question

.A cylinder of compressed gas has a pressure of 4.9 atm in one day. The next day, the same

cylinder of gas has a pressure of 4.7 atm, and its temperature is 8°C. What was the
temperature on the previous day in °C?

Answer 1

We can use the ideal gas law to solve for the initial temperature of the gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

We can assume that the number of moles and volume of gas are constant, since the problem states that it is the same cylinder of gas. Therefore, we can write:

P1/T1 = P2/T2

where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure, and T2 is the final temperature.

Substituting the values given in the problem, we get:

4.9/T1 = 4.7/281

Solving for T1, we get:

T1 = 4.9 × 281 / 4.7

T1 = 293 K

Converting to Celsius, we get:

T1 = 20°C

Therefore, the initial temperature of the gas was 20°C.