Question

Solve the following equation

3x²+x-12
= 1
b
Od
x=-12 x=11
x=4 x=-3
x=12 x=-1
x=3 x=-4

Answer 1

3x^2+x-13 =1
Answer = step 1:
Move terms to the left side
Subtract the numbers
3x^ + x - 12 = 1

Step 2:
Use the quadratic formula:
(-b±√(b²-4ac))/(2a)

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

3x^2 + x - 13 = 0
a=3
b=1
c=-13
(-1±√(1²-4*3(-13)/(2*3)

Step 3:
Evaluate the exponent

Multiply the numbers

Add the numbers

Multiply the numbers

X= (-1±√(1²-4*3(-13)/(2*3)

X= (-1±√(157)/(6)

Step 4:
To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

X= (-1+√(157)/(6)

X= (-1-√(157)/(6)

Step 5:
Rearrange and isolate the variable to find each solution.

X= (-1+√(157)/(6)

X= (-1-√(157)/(6)

Solution = X= (-1±√(157)/(6)