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Write an equation of a circle with the given center and radius. center (3,4) and radius 6 (x-3)^2+(y-4)^2=36 (x-3)^2+(y-4)^2=6 (x+3)^2+(y-4)^2=36 (x+3)^2+(y-4)^2=6

Write an equation of a circle with the given center and radius. center (3,4) and radius 6 (x-3)^2+(y-4)^2=36 (x-3)^2+(y-4)^2=6 (x+3)^2+(y-4)^2=36 (x+3)^2+(y-4)^2=6
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Write an equation of a circle with the given center and radius. center (3,4) and radius 6

(x-3)^2+(y-4)^2=36
(x-3)^2+(y-4)^2=6
(x+3)^2+(y-4)^2=36
(x+3)^2+(y-4)^2=6

User Tal Folkman
by
8.6k points

1 Answer

4 votes

Answer:


{(x - 3)}^(2) + {(y - 4)}^(2) = 36

User Migpics
by
8.3k points
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