Question

The pain reliever morphine contains 17.900 g C, 1.680 g H, 4.225 g O, and 1.228 g N. Determine the empirical Formula.

Answer 1

Answer: The empirical formula is
`C_(17)H_(19)O_3N`

Step-by-step explanation:

Mass of C= 17.900 g

Mass of H = 1.680 g

Mass of O = 4.225 g

Mass of N = 1.228 g

Step 1 : convert given masses into moles.

Moles of C =
`\frac{\text{ given mass of C}}{\text{ molar mass of C}}= (17.990g)/(12g/mole)=1.5moles`

Moles of H =
`\frac{\text{ given mass of H}}{\text{ molar mass of H}}= (1.680g)/(1g/mole)=1.680moles`

Moles of O =
`\frac{\text{ given mass of O}}{\text{ molar mass of O}}= (4.225g)/(16g/mole)=0.264moles`

Moles of N =
`\frac{\text{ given mass of N}}{\text{ molar mass of N}}= (1.228g)/(14g/mole)=0.087moles`

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =
`(1.5)/(0.087)=17`

For H =
`(1.680)/(0.087)=19`

For O =
`(0.264)/(0.087)=3`

For N =
`(0.087)/(0.087)=1`

The ratio of C : H: O: N = 17: 19: 3: 1

Hence the empirical formula is
`C_(17)H_(19)O_3N`