Question

40(7−5x)<7−25(8x+2) ​

Answer 1

To solve the inequality 40(7−5x)<7−25(8x+2), we can start by distributing the 40 on the left side and the -25 on the right side:

280 - 200x < 7 - 200x - 50

Next, we can combine like terms on both sides:

230 - 200x < -200x - 43

Now, we can add 200x to both sides:

230 < -43

This is a false statement, which means that there is no solution to the inequality. Therefore, the inequality 40(7−5x)<7−25(8x+2) is false for all values of x.