Question

Multiply these polynomials SHOW YOUR WORK
(2x^2-3x+4)(3x^2+2x-1)

Answer 1

`6x^(4)` -
`5x^(3)` +
`4x^(2)` + 11x - 4

Explanation:

The equation must be FOILed (Basically, multiply every term in the first part of the equation by every term in the second part.)

First, we multiply
`2x^(2)` by
`3x^(2)`, 2x, and -1

`2x^(2)` *
`3x^(2)` =
`6x^(4)`

`2x^(2)` * 2x =
`4x^(3)`

`2x^(2)` * -1 = -
`2x^(2)`

Then, we multiply -3x by
`3x^(2)`, 2x, and -1

-3x *
`3x^(2)` =
`-9x^(3)`

-3x * 2x =
`-6x^(2)`

-3x * -1 = 3x

Then, we multiply 4 by
`3x^(2)`, 2x, and -1

4 *
`3x^(2)` =
`12x^(2)`

4 * 2x = 8x

4 * -1 = -4

Finally, we add all these terms together.

`6x^(4)` +
`4x^(3)` -
`2x^(2)` -
`9x^(3)` -
`6x^(2)` + 3x +
`12x^(2)` + 8x - 4

Combining like terms, we will get a final answer of

`6x^(4)` -
`5x^(3)` +
`4x^(2)` + 11x - 4