Question

Calculate the specific heat of a substance that increases 5°C when 200 J are added to 10 g of the substance.

Answer 1

0.072 J/kg*K

Known Equation

Specific Heat [
`(Joules)/(kilogram*Kelvin)`] = c =
`(Q)/(m(T_(2)-T_(1)))`

where Q [J] = Heat, m [kg] = mass, and ΔT [K] = change in temperature

Given Variables

Q = 200 J

m = 10 g

ΔT = 5 °C = 5 °C + 273 = 278 K

Solve

Specific Heat = c = (200 J) / (10 g * 278 K) = 0.072 J/kg*K