Answer:
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Find the sum of the volumes of the two given cones.
Cone volume:
Cone 1, d = 4m, h = 8m:
- V = 1/3 π*(4/2)²*8 = 32π/3 m³
Cone 2, r = 2m, h = 6 m:
Total volume:
- V = 32π/3 + 8π = 56π/3 m³ = 58.64 m³ (rounded)