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100.0 mL of a 0.630 M solution of KBr is diluted to 500.0 mL. What is

the new concentration of the solution?

100.0 mL of a 0.630 M solution of KBr is diluted to 500.0 mL. What is the new concentration-example-1
User Erik Dietrich
by
3.2k points

1 Answer

6 votes
6 votes

Answer:

C2= 0.126M

Step-by-step explanation:

C1*V1=C2*V2

C1= 0.630M

C2=?

V1= 100.0ML

V2= 500.0ML

0.630*100 = C2*500

C2= 0.630*100÷500

C2= 63÷500

C2= 0.126M

User Jmartins
by
2.4k points