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What is an equation for the ellipse with foci (0, -5) and (0,5) and vertices (0, -9) and (0, 9)

User Harms
by
8.1k points

2 Answers

5 votes

Answer:

x^2 / 81 + y^2 / 56 = 1

Explanation:

The center of the ellipse is at the midpoint of the foci, which is (0,0). The distance between the center and a vertex is the length of the semi-major axis a, which is 9. The distance between the center and a focus is c, which is 5. The equation for the ellipse is:

(x-0)^2 / 9^2 + (y-0)^2 / b^2 = 1

where b is the length of the semi-minor axis. To find b, you use the relationship:

b^2 = a^2 - c^2

b^2 = 9^2 - 5^2

b^2 = 56

Therefore, the equation for the ellipse is:

x^2 / 81 + y^2 / 56 = 1

User Adel Sal
by
8.3k points
1 vote

Answer:

0,8

Explanation:

User MTeck
by
7.6k points

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