Question

A bowl has 27 red M&Ms and 32 green M&Ms. John randomly chooses a M&M, eats it, and then chooses another M&M. What is the probability that both M&Ms are green? Show your work. What is the probability that John eats a red M&M then a green M&M? Show your work.

Answer 1

Answer: Both Green: 29%; Red then Green: 25%

Step-by-step explanation: Both Green: 32/59 * 31/58 = 0.28988 = 29%

Red then Green: 27/59 * 32/58 = 0.2524 = 25%