218k views
5 votes
Find m/_I. I need help on solving this problem please?

Find m/_I. I need help on solving this problem please?-example-1
User Tyrone
by
7.5k points

2 Answers

0 votes

Answer:

60°

Explanation:

You want the measure of angle I in right triangle HIJ, given that the side opposite is 3√30 and the side adjacent is 3√10.

Tangent

The tangent relation is ...

Tan = Opposite/Adjacent

In this triangle, ...

tan(I) = (3√30)/(3√10) = √(30/10) = √3

Then the angle is ...

I = arctan(√3) = 60°

The measure of angle I is 60°.

__

Additional comment

The trig functions of 30° and 45° and their relationships to each other are based on the side relationships of the two "special" right triangles:

30°-60°-90° triangle has side ratios 1 : √3 : 2

45°-45°-90° triangle has side ratios 1 : 1 : √2

Of course, side lengths are in the same order as their opposite angles.

The mnemonic SOH CAH TOA can help you remember the necessary relationships:

  • Sin = Opposite/Hypotenuse
  • Cos = Adjacent/Hypotenuse
  • Tan = Opposite/Adjacent
Find m/_I. I need help on solving this problem please?-example-1
User Hacklikecrack
by
7.6k points
5 votes

Answer:

∠ I = 60°

Explanation:

using the tangent ratio in the right triangle

tan I =
(opposite)/(adjacent ) =
(HJ)/(IJ) =
(3√(30) )/(3√(10) ) =
(√(30) )/(√(10) ) =
\sqrt{(30)/(10) } =
√(3) , then

∠ I =
tan^(-1) (
√(3) ) = 60°

User Jet  Chopper
by
8.5k points