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3 votes
Miss Wan and Miss Lim left their school at 2.50 p .m and drove along the same

route to Orchard Road. Miss Wan drove at an average speed of 60 Km/h and
reache Orchard Road 30 min later. Meanwhile, Miss Lim was still 5 km away from Orchard
Road.
a) What was the Miss Lim's average speed for the whole journey?

b) What time would Miss Lim reach Orchard Road?

User UXCODA
by
8.3k points

2 Answers

3 votes

Answer and explanation:

a) To find the average speed of Miss Lim for the whole journey, we need to use the formula:

Average speed = Total distance ÷ Total time

Let's first calculate the total distance traveled by both Miss Wan and Miss Lim. We know that Miss Wan drove at an average speed of 60 km/h and reached Orchard Road 30 minutes later. So, the total distance traveled by her would be:

Distance = Speed × Time

Distance = 60 km/h × (30/60) h

Distance = 30 km

Now, we also know that Miss Lim was still 5 km away from Orchard Road when Miss Wan reached there. Therefore, the total distance traveled by both of them would be:

Total distance = Distance covered by Miss Wan + Distance left for Miss Lim

Total distance = 30 km + 5 km

Total distance = 35 km

Next, let's calculate the total time taken by both of them. We know that Miss Wan took 30 minutes less than Miss Lim to reach Orchard Road. So, if we assume that Miss Lim took t hours to reach Orchard Road, then Miss Wan took (t - 0.5) hours. Therefore, the total time taken by both of them would be:

Total time = Time taken by Miss Wan + Time taken by Miss Lim

Total time = (t - 0.5) h + t h

Total time = 2t - 0.5 h

Now, we can use the formula to find the average speed of Miss Lim:

Average speed = Total distance ÷ Total time

Average speed = 35 km ÷ (2t - 0.5) h

Therefore, the average speed of Miss Lim for the whole journey is 35/(2t-0.5) km/h.

b) To find out what time Miss Lim would reach Orchard Road, we can use the formula:

Time taken = Distance ÷ Speed

We know that Miss Lim was 5 km away from Orchard Road when Miss Wan reached there. Therefore, the distance left for Miss Lim to cover would be:

Distance = 5 km

We also know that Miss Lim's average speed for the whole journey is 35/(2t-0.5) km/h. Therefore, the time taken by her to cover the remaining distance of 5 km would be:

Time taken = Distance ÷ Speed

Time taken = 5 km ÷ 35/(2t-0.5) km/h

Time taken = (2t - 0.5) ÷ 7 h

Now, we need to add this time to the time when Miss Wan reached Orchard Road, which was 30 minutes past 2.50 p.m. So, the time when Miss Lim would reach Orchard Road would be:

Time = Time when Miss Wan reached Orchard Road + Time taken by Miss Lim

Time = 2.50 p.m. + 30 min + (2t - 0.5) ÷ 7 h

Simplifying this equation, we get:

Time = (14t + 11) ÷ 14 p.m.

Therefore, Miss Lim would reach Orchard Road at (14t + 11) ÷ 14 p.m.

User Petri
by
8.3k points
4 votes

Answer:

a) 50 km/h

b) 3:26 p.m.

Explanation:

You want to know Miss Lim's average speed and arrival time at Orchard Road if Miss Wan gets there in 30 minutes at 60 km/h, starting at 2:50 pm.

Distance

The distance Miss Wan traveled is ...

distance = speed × time

distance = (60 km/h) × (1/2 h) = 30 km

a) Speed

In the same 30 minutes that Miss Wan traveled 30 km, Miss Lim traveled 5 km less, so 30 -5 = 25 km. Miss Lim's speed was ...

speed = distance/time

speed = (25 km)/(1/2 h) = 50 km/h

Assuming Miss Lim maintained that speed for the remaining 5 km, her average speed for the journey was 50 km/h.

b) Time

Miss Lim's travel time is ...

time = distance/speed

time = (30 km)/(50 km/h) = 3/5 h = 36 min

The clock time 36 minutes after 2:50 pm is 3:26 pm.

Miss Lim reached Orchard Road at 3:26 p.m..

User Hookedonwinter
by
8.1k points