Answer:
61°
Explanation:
You want the angle XCA in the figure, given that angle XBA is 70°, and ABCD is a rectangle with AB=5.6m and BC=6.4m. Angles at A are right angles.
Diagonal
The length of diagonal AC is found using the Pythagorean theorem.
AC² = AB² +BC²
AC = √(5.6² +6.4²) = 0.8√113 ≈ 8.504 . . . . meters
Height
The length XA is found using the tangent function:
Tan = Opposite/Adjacent
tan(B) = XA/AB
XA = AB·tan(B) = 5.6·tan(70°) . . . . meters
Angle
The angle XCA is found from the tangent relation:
tan(XCA) = XA/AC
tan(XCA) = 5.6·tan(70°)/(0.8√113) = 7·tan(70°)/√113
angle XCA = arctan(7·tan(70°)/√113) ≈ 61.07°
The angle XC makes with the horizontal is about 61°.