Question

Equation of a line with slope m=−2/5 that contains the point (10,−5).

Answer 1

y = (-2/5)x+b

Explanation:

First plug these into the y=mx+b equation:

-5 = (-2/5)(10)+b.

Then solve for b:

-5 = -4+b

Add 4 to both sides:

-1 =b.

Therefore, the equation of the line is y = (-2/5)x+b. You can also double check this by plugging 10 into the equation we just obtained.

Answer 2

The equation of a line with slope m = -2/5 that contains the point (10,-5) can be found using the point-slope form of the equation of a line:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope.

Substituting the given values, we get:

y - (-5) = (-2/5)(x - 10)

Simplifying the right side, we get:

y + 5 = (-2/5)x + 4

Subtracting 5 from both sides, we get:

y = (-2/5)x - 1

Therefore, the equation of the line with slope m = -2/5 that contains the point (10,-5) is y = (-2/5)x - 1.