Question

What is the mass (in g) of a solid piece of iron which has a specific heat of 0.449 J/g°C if when it absorbed 948.0 J of heat the temperature rose from 24.0°C to

82.1°C? Give your answer in 3 sig figs.

Answer 1

Step-by-step explanation:

We can use the formula:

q = mcΔT

where q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Given:
specific heat of iron (c) = 0.449 J/g°C
initial temperature (T1) = 24.0°C
final temperature (T2) = 82.1°C
heat absorbed (q) = 948.0 J

Substituting the given values into the formula, we get:

q = mcΔT
948.0 J = m(0.449 J/g°C)(82.1°C - 24.0°C)
948.0 J = m(0.449 J/g°C)(58.1°C)
m = 948.0 J ÷ (0.449 J/g°C × 58.1°C)
m = 33.1 g

Therefore, the mass of the iron piece is 33.1 g (to three significant figures)